Print 58 comment(s) - last by AntDX316.. on May 18 at 4:10 AM

2.0 GHz memory frequencies? No problem.

Anh beat me to R600 benchmarks by a few mere hours -- when you snooze, you lose at DailyTech. Needless to say, I feel somewhat compelled to add my benchmarks to the mix as well. 

The system I'm using is an Intel Core 2 Extreme QX6800, ASUS P5N32SLI-E with 2x2GB DDR2-800.  My tests this morning used the Catalyst 8.361 RC4 driver.  The card used was a Radeon HD 2900 XT 512MB.

Core Clock
Memory Clock
745 MHz
800 MHz
800 MHz
900 MHz
845 MHz
950 MHz
845 MHz
995 MHz

Like Anh, I was able to get pretty close to a 2.0GHz memory clock while still keeping the system stable.  For reference, my GeForce 8800 GTX (core clock at 650 MHz, memory at 2.0 GHz) scores 14128 (1280x1024) and 11867 (1600x1200) on the same system with ForceWare 158.19. 

I'm currently benchmarking the Radeon HD 2900 XTX, though I'll revist the XT if anyone has any particular requests.

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RE: so...
By Schmide on 4/25/2007 2:01:41 PM , Rating: 2
Conversation of energy!!!

Consumed power is directly related to heat output, The chip is basically a very complex variable resistor and there is nowhere else for the energy to go. If it uses it, it must go somewhere. It goes to HEAT!!! Efficiency is directly related to power usage which is directly related to heat output.

RE: so...
By Goty on 4/25/2007 6:04:44 PM , Rating: 1
Exactly, if a chip is 100% efficient, then it will use all the power it is supplied with, leaving none left over to be wasted as heat. Semiconductors are inherently resistive, as you stated, and so some is wasted as heat. The type of semiconductor used, as well as its dopants, all affect it's current characteristics. Some combinations are more efficient than others due to their relative band gaps so they will waste less current as heat than other combinations.

Different manufacturing processes also play a part in efficiency because of the fact that the dielectric used in the transistors gets smaller as the size of the individual transistor goes down. The thinner the dielectric, the more current that is allowed to leak out as heat.

RE: so...
By dunno99 on 4/25/2007 8:30:39 PM , Rating: 3
Don't want to start a flame war or anything, but despite you being able to use a bunch of terms from an EE lecture, you're missing the point about where that energy goes. Remember back in physics, a circuit has to use up all the voltage difference between the source and sink (usually ground)?

Since we know that these graphics cards need some finite amount of current (I) at a certain voltage (V), we know that the power it uses is P = IV. And according to the laws of thermodynamics, energy (and power) is conserved.

Therefore, If P = IV amount of watts is used by the graphics card, where does the energy go? Most likely, the card doesn't have a huge battery or capacitor storing up the energy just to mess with you. So, everything turns into heat in the end (we're not talking about heat death here, just the usage of the video card). Therefore, if a card consumes 1000W of power, it will output 1000W of heat, no matter what. Efficiency just means how much of that power is used to do something "useful."

As a final note, I'll just use an example. Assume you have an adder circuit that absolutely requires 1V at 1A. The power it uses is 1W. Its efficiency we would say, is 100%. However, if you put a huge resistor in front of the adder (in series) that is rated at 1 Ohm, then you would need to raise the voltage input to 2V in order for the adder to do its job. Now, we know that of the 2W you put in, only 1W is doing the actual work, and the rest are wasted. In this case, the efficiency is 50% for the entire circuit.

RE: so...
By Schmide on 4/25/2007 8:59:32 PM , Rating: 2
I really suck at this efficiency crap, but wouldn't any semiconductor be considered 0% efficient, because it basically does no work. When you say a light bulb is say 90% efficient, this means it converts 90% of its energy to light and 10% to heat. A semiconductor produces no light or kinetic movement so it is basically 100% inefficient, and contributes to a circuit exactly the same as a resistor.

RE: so...
By sxr7171 on 4/26/2007 1:40:24 AM , Rating: 2
Yes. Everything becomes heat. There is no "work" in the physical sense.

RE: so...
By dunno99 on 4/26/2007 9:57:37 AM , Rating: 2
Just like sxr7171 said, work is really just how you define it. If you wanted a heater, then a video card is pretty much 100% efficient (discounting generated electromagnetic radiation and whatnot).

In the case of a graphics card, we would consider the ideal amount of power to perform computations and information exchange at the specs of the graphics card, and compare that figure to what it's actually using.

RE: so...
By KCvale on 4/26/2007 10:55:07 AM , Rating: 2
An incandesent light bulb is only about 5% efficent (the light), the other 95% of the energy is wasted on heat.
Thats why the push for the world to change to the new coiled floresent bulbs.
They are over twice as efficent putting about 12% of the power to light using less power (a 20W floresent puts out as much light as a 75W bulb) and last 5 times longer.

A semiconductor is an "active" device, the "work" they perform is the millions of logic gates inside a chip being switched on and off millions of times a second and held in a given state (on or off) the entire time.

Resistors are a "static" device that simply restricts the flow of DC current by disapating it as heat (in series), or redirects the current flow (and voltage) when in parallel.

Nothing involving electricity is 100% efficient, not even wire.
Buy using better materials and using lower voltages semiconductors are becoming more efficient, but they always produce some waste in the form of heat.

RE: so...
By Howard on 4/25/2007 9:24:53 PM , Rating: 2
Jesus Christ. All the power used by a chip is turned into heat.

RE: so...
By johnsonx on 4/26/2007 5:23:37 PM , Rating: 1
Actually I think the poster's name was 'Goty'. I haven't seen Jesus Christ here in awhile.

“So far we have not seen a single Android device that does not infringe on our patents." -- Microsoft General Counsel Brad Smith

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